November 7 Math Homework

Pg. 193-194 Problem Set D

(Note: For problems 1-4 with the tables, the numbers don't match up because I didn't want to take the time to put tables in. Sorry for the inconvinience.)
1.
(x,y) (0,0) (4,4) (36,16) (25,0.25) (0,100)
√(x)+√(y) 0 4 10 5.5 10
√(x+y) 0 √8 √52 √25.25 10
The table shows that you cannot distribute the square root symbol over the addition because the values are not the same.
2.
(x,y) (0,0) (5,5) (9,25) (0.64,100) (0,100)
√(x)*√(y) 0 5 15 8 0
√(x*y) 0 5 15 8 0
The table shows that you can distribute the square root symbol over the multiplication because the values are not the same.
3. (x,y) (0,0) (4,4) (81,49) (25/9,16/9) (0,100)
√(x)-√(y) 0 0 2 1/3 -10
√(x-y) 0 0 √32 1 Undefined
The table shows that you cannot distribute the square root symbol over the subtraction because the values are not the same.
4. (x,y) (0,2) (3,3) (4,16) (4/9,2.25) (0,100)
√(x)/√(y) 0 1 0.5 4/9 0
√(x/y) 0 1 0.5 4/9 0
The table shows that you can distribute the square root symbol over the division because the values are the same.


Pg. 195 Problem Set E

1. 5√3
2. 2√15
3. Cannot be simplified
4. 0.5√0.5
5. 5x√2x
6. 6(a^2)(b^2)√2b
7. √12
8. √72
9. √75y^2
10. √(3/16)x^5


Pg. 196 Problem Set F

1. No √2+√2+√2 = 3√2 = √18
√6 = √6
2. No 3√2+√3 do not simplify to anything.
3. Yes √50+√98 = 5√2+7√2=12√2
12√2 = 12√2
4. Yes √45+√20-7√5 = 3√5+2√5-7√5 = -2√5
(-1/2)√80 = -2√5
5. √75-√27
6ai. √3
6aii. √3
6aiii. 5√2
6aiv. 5√2
6b. Yes, i and ii are equivalent
iii and iv are equivalent



Note: It is possible that there is a typo or that I have made a calculation mistake. I do not take any blame for wrong answers.